[Tuna Mayonnaise (tsuyomayo)] Bakunyuu Sister x Kyokon Goblin [English]

[Tuna Mayonnaise (tsuyomayo)] Bakunyuu Sister x Kyokon Goblin [English]

[ツナマヨネーズ (tsuyomayo)] 爆乳シスター×巨根ゴブリン [英訳]

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WhyDoIHaveToWriteSomething
WhyDoIHaveToWriteSomething
5. Assuming that goblins babies grow at a similar rate as humans infants, with the same nutrients, respectively, we can take the recommendation of the WHO to breastfeed 2 years. Since she produces 50 Tons per day, over two years it would be: 50 T/d × 730 d = 315,000 Tons = 3.15 × 10^8 kg Which is equal to 158 full Tesla cars, 3150 blue whales or the fundament of the Burj khalifa. With a density of 1030kg/m^3, it would take up a Volume of: 3.15 × 10^8 kg/1030 kg/m^3 = 3 × 10^5 m^3 Assuming she is addicted to getting laid by the goblin getting impregnated every time after birth, for roughly 26 times, breastfeeding 20 years straight she could fill up the whole alliance arena in Germany. To replace the whole water on earth, which is 1.4 × 10^12 m^3, with her breast milk, she would need: 1.4 × 10^12 m^3/50 m^3 per day = 2.8 × 10^10 days or 77 million years; which is approximately 12 times the human history
WhyDoIHaveToWriteSomething
WhyDoIHaveToWriteSomething
4. Since the goblin impregnated her, she will get pregnant. During pregnancy breasts typically enlarge by around 30%: V = 0.16m^3 × 1.3 = 0.208m^3 Around 40% of the breasts volume is functional mammary gland (that produces milk), therefore 0.0832m^3. The density of it is around 1,1g/cm^3 so 1100kg/m^3: m = p × V m_mammary gland = 0.0832m^3 × 1100kg/m^3 = 91.52kg m_breast = 0.208m^3 × 985kg/m^3 = 204.88kg each The mammary gland is 0.0832m^3 in Volume equal to 83200cm^3. A rough calculation of milk production per day per cm^3 of mammary gland (data from some studies): 600ml/d on 2cm^3 of functional mammary gland, therefore 300ml/per day per cm^3. This leads to a total milk production of: 83,200cm^3 × 0.3L/(day × cm^3) = 24,960L/day So during pregnancy she will produce roughly 25 Tons of milk per day, per breast. Since she has two there will be a total production of around 50 Tons of milk from breasts with a mass of 205kg, respectively.
WhyDoIHaveToWriteSomething
WhyDoIHaveToWriteSomething
3. From the 6th picture we see her breasts stretch out to shoulder width, so we can assume that the diameter of one breast is half the shoulder width, hence d = 0.33m. The radius r = d/2 = 0.165m The Area A = 2π × r^2 = 0.171 m^2 Therefore the Volume is: V = A × h = 0.171m^2 × 0.936m = 0.16m^3 The average density of a human body is 985kg/m^3, hence: m = p × V = 985kg/m^3 × 0.16m^3 =158kg So her breasts weight 158kg each. But she got impregnated, so what about that???
WhyDoIHaveToWriteSomething
WhyDoIHaveToWriteSomething
2. If we assume the stones on the 12th and the 29th picture are the same, then her upper body (from head to ass) is a bit less than 4m. So from the upper end of the hipbone to her head should be around 3.5m. On my phone if I click on the 29th picture: from shoulder to head 1.5cm and from hand to head 4.5cm. Through the rule of three we now know her arm is 1.17m long. On the 20th picture on my phone her arms are 5cm and her breast are 4cm. Using the rule of three again we now know that her breast is 0.936m long. From the 20th picture, we can approximate that her breasts are cylindrical. According to some studies the average shoulder width of US. females is 38cm and the average Arm length is 60-74cm (67cm). From there we can calculate the ratio: 38cm/67cm = 0.567 Therefore her shoulder width is: 1.17m × 0.567 = 0.66m
WhyDoIHaveToWriteSomething
WhyDoIHaveToWriteSomething
Since all the sizes are so absurd, I will be that guy, who estimates the weight of her breasts: To get to that we need to know the height of the trees. After some research I think they could be Beech, due to the shape of the leaves (pointed), they are green in summer (I assume it is summer, otherwise it would be way to cold to fuck in a forest at night), no rhytidomes (rather smooth) and the grayish/brown wood texture. Old beech can get over 40m tall and I assume the forest is old, but since there are no rhytidomes they are not in their last years, so I will go with 40m of height. From the 12th picture I approximated that the stone, on which the goblin sits, is 45m from the trees and she stands 5m from the stone. Thereby, using the Intercept Theorem, we can calculate the stones height: Z being the end of her foot A the stones bottom A' the trees bottom B the stones top B' the trees top Therefore: AB/A'B' = ZA/ZA' AB = (ZA × A'B')/ZA' AB = (5m × 40m)/50m = 4m
Sugarbexrss
Sugarbexrss
Finally in english
mangaman24
mangaman24
Best hentai out rn hands down argue wit yah selves
Zenou
Zenou
Her body = 😍😍😍 meaty asshole ❤💞💕🌰🌰🌰
Arop
Arop
Very very good
Peternak Kampret
Peternak Kampret
Gw tau ini MTL. Tapi minimal fontnya dibagusin dikit lah.